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0.16=0.8x-x^2
We move all terms to the left:
0.16-(0.8x-x^2)=0
We get rid of parentheses
x^2-0.8x+0.16=0
a = 1; b = -0.8; c = +0.16;
Δ = b2-4ac
Δ = -0.82-4·1·0.16
Δ = 1.11022302463E-16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.8)-\sqrt{1.11022302463E-16}}{2*1}=\frac{0.8-\sqrt{1.11022302463E-16}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.8)+\sqrt{1.11022302463E-16}}{2*1}=\frac{0.8+\sqrt{1.11022302463E-16}}{2} $
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